Integrand size = 19, antiderivative size = 58 \[ \int \frac {c+d x^2}{\sqrt {a+b x^2}} \, dx=\frac {d x \sqrt {a+b x^2}}{2 b}+\frac {(2 b c-a d) \text {arctanh}\left (\frac {\sqrt {b} x}{\sqrt {a+b x^2}}\right )}{2 b^{3/2}} \]
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Time = 0.01 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {396, 223, 212} \[ \int \frac {c+d x^2}{\sqrt {a+b x^2}} \, dx=\frac {\text {arctanh}\left (\frac {\sqrt {b} x}{\sqrt {a+b x^2}}\right ) (2 b c-a d)}{2 b^{3/2}}+\frac {d x \sqrt {a+b x^2}}{2 b} \]
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Rule 212
Rule 223
Rule 396
Rubi steps \begin{align*} \text {integral}& = \frac {d x \sqrt {a+b x^2}}{2 b}-\frac {(-2 b c+a d) \int \frac {1}{\sqrt {a+b x^2}} \, dx}{2 b} \\ & = \frac {d x \sqrt {a+b x^2}}{2 b}-\frac {(-2 b c+a d) \text {Subst}\left (\int \frac {1}{1-b x^2} \, dx,x,\frac {x}{\sqrt {a+b x^2}}\right )}{2 b} \\ & = \frac {d x \sqrt {a+b x^2}}{2 b}+\frac {(2 b c-a d) \tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a+b x^2}}\right )}{2 b^{3/2}} \\ \end{align*}
Time = 0.16 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.12 \[ \int \frac {c+d x^2}{\sqrt {a+b x^2}} \, dx=\frac {d x \sqrt {a+b x^2}}{2 b}+\frac {(2 b c-a d) \text {arctanh}\left (\frac {\sqrt {b} x}{-\sqrt {a}+\sqrt {a+b x^2}}\right )}{b^{3/2}} \]
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Time = 2.29 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.81
method | result | size |
risch | \(\frac {d x \sqrt {b \,x^{2}+a}}{2 b}-\frac {\left (a d -2 b c \right ) \ln \left (x \sqrt {b}+\sqrt {b \,x^{2}+a}\right )}{2 b^{\frac {3}{2}}}\) | \(47\) |
default | \(\frac {c \ln \left (x \sqrt {b}+\sqrt {b \,x^{2}+a}\right )}{\sqrt {b}}+d \left (\frac {x \sqrt {b \,x^{2}+a}}{2 b}-\frac {a \ln \left (x \sqrt {b}+\sqrt {b \,x^{2}+a}\right )}{2 b^{\frac {3}{2}}}\right )\) | \(63\) |
pseudoelliptic | \(\frac {\sqrt {b \,x^{2}+a}\, d x \sqrt {b}-\operatorname {arctanh}\left (\frac {\sqrt {b \,x^{2}+a}}{x \sqrt {b}}\right ) a d +2 \,\operatorname {arctanh}\left (\frac {\sqrt {b \,x^{2}+a}}{x \sqrt {b}}\right ) b c}{2 b^{\frac {3}{2}}}\) | \(64\) |
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Time = 0.26 (sec) , antiderivative size = 113, normalized size of antiderivative = 1.95 \[ \int \frac {c+d x^2}{\sqrt {a+b x^2}} \, dx=\left [\frac {2 \, \sqrt {b x^{2} + a} b d x - {\left (2 \, b c - a d\right )} \sqrt {b} \log \left (-2 \, b x^{2} + 2 \, \sqrt {b x^{2} + a} \sqrt {b} x - a\right )}{4 \, b^{2}}, \frac {\sqrt {b x^{2} + a} b d x - {\left (2 \, b c - a d\right )} \sqrt {-b} \arctan \left (\frac {\sqrt {-b} x}{\sqrt {b x^{2} + a}}\right )}{2 \, b^{2}}\right ] \]
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Time = 0.26 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.41 \[ \int \frac {c+d x^2}{\sqrt {a+b x^2}} \, dx=\begin {cases} \left (- \frac {a d}{2 b} + c\right ) \left (\begin {cases} \frac {\log {\left (2 \sqrt {b} \sqrt {a + b x^{2}} + 2 b x \right )}}{\sqrt {b}} & \text {for}\: a \neq 0 \\\frac {x \log {\left (x \right )}}{\sqrt {b x^{2}}} & \text {otherwise} \end {cases}\right ) + \frac {d x \sqrt {a + b x^{2}}}{2 b} & \text {for}\: b \neq 0 \\\frac {c x + \frac {d x^{3}}{3}}{\sqrt {a}} & \text {otherwise} \end {cases} \]
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Time = 0.19 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.81 \[ \int \frac {c+d x^2}{\sqrt {a+b x^2}} \, dx=\frac {\sqrt {b x^{2} + a} d x}{2 \, b} + \frac {c \operatorname {arsinh}\left (\frac {b x}{\sqrt {a b}}\right )}{\sqrt {b}} - \frac {a d \operatorname {arsinh}\left (\frac {b x}{\sqrt {a b}}\right )}{2 \, b^{\frac {3}{2}}} \]
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Time = 0.28 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.84 \[ \int \frac {c+d x^2}{\sqrt {a+b x^2}} \, dx=\frac {\sqrt {b x^{2} + a} d x}{2 \, b} - \frac {{\left (2 \, b c - a d\right )} \log \left ({\left | -\sqrt {b} x + \sqrt {b x^{2} + a} \right |}\right )}{2 \, b^{\frac {3}{2}}} \]
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Time = 5.15 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.48 \[ \int \frac {c+d x^2}{\sqrt {a+b x^2}} \, dx=\left \{\begin {array}{cl} \frac {d\,x^3+3\,c\,x}{3\,\sqrt {a}} & \text {\ if\ \ }b=0\\ \frac {c\,\ln \left (\sqrt {b}\,x+\sqrt {b\,x^2+a}\right )}{\sqrt {b}}-\frac {a\,d\,\ln \left (2\,\sqrt {b}\,x+2\,\sqrt {b\,x^2+a}\right )}{2\,b^{3/2}}+\frac {d\,x\,\sqrt {b\,x^2+a}}{2\,b} & \text {\ if\ \ }b\neq 0 \end {array}\right . \]
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